c# - How does DoubleUtil.DoubleToInt(double val) work? -


the ms.internal.doubleutil-class contains function

public static int doubletoint(double val) {     return (0 < val) ? (int)(val + 0.5) : (int)(val - 0.5); }

i wonder why 'converts' val integer?

the cast double int takes floor, adding .5 (or subtracting .5 if negative) means 1.6 returns 2, while 1.4 return 1.


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