c++ - Is everything cleaned up when using 'goto'? -


this question has answer here:

for (int = 0 ; < 10 ; ++i) {     (int j = 0 ; j < 10 ; ++j)     {         goto label;     } } label: // stuff

after goto i , j variables freed? recall goto doesn't unwind stack or cleanup screw in case?

yeah, gets cleaned up. because c++ frees variables go out of scope.


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