java - change the bits order -

i have function converts int hex. in function, seekbar's value between 0 , 100. changes , convert hex.

    private string decimaltohex(int i) {      /**conversion decimal of seekbar's % value*/     int_value = ((i * 20480) / 100) * -1;     int_value = -20480 - int_value;      /**conversion hex*/     hex_value = integer.tostring(int_value, 16);     //hex_value = integer.tohexstring(c2_final);      return hex_value; } 

lets suppose int i value 52. gets next value: int_value = -9831

when convert value hex, -2667. not value need.

i need make conversion gives me hex result value "d999". value ones-complementing value (aka ~ operator). converting value -9831 positve 9831, substracting 1 9830, , last, changing bits value 55705 in hex d999.

how can last thing? change bits?

code in c:

if (int_value < 0) {          c2_value = int_value * -1;         c2_value = c2_value - 1;         c2_final = ~c2_value;     } 

java.lang.integer provides tohexstring() method converts specified integer hexadecimal string representation.

you can use following.

log.d(tag, java.lang.integer.tohexstring(-9831)); 

this give output

08-07 18:53:57.643: d/home(31698): ffffd999 

to output, use following code.

string strhex = java.lang.integer.tohexstring(-9831); if (strhex.length() > 4)     log.d(tag, strhex.substring(4)); else     log.d(tag, strhex);