bash - Escape awk $ in shell function of bashrc -

i have command gets next id of table pool of sql files, trying put command alias in ~/.bashrc using shell function, did not figure out how escape $ gets awk , not replaced bash, here's code in .bashrc:

function nextval () {     grep 'insert \""$1"\"' *.sql | \     awk '{print $6}' | \     cut -c 2- | \     awk -f "," '{print $1}' | \     sort -n | \     tail -n 1 | \     awk '{print $0+1}' }  alias nextval=nextval 

usage: # nextval tablename

escaping \$ error: awk: backslash not last character on line. $ not inside double quotes, why bash replacing ?

perhaps part need change this

'insert \""$1"\"' 

to

"insert \"$1\""