I need help coming up with a function in python that can take 3 arguements as lists and give me all combinations of there elements -


this question has answer here:

what have far pretty nothing 

def dress_me(shirt, tie, suit):    #    if type(shirt) != list or type(tie) != list or type(suit) != list:     #        return none             combinations = dress_me(shirt, tie, suit)             combo in combinations:                 print(combo)

use itertools.product:

def dress_me(shirt, tie, suit):     if type(shirt) != list or type(tie) != list or type(suit) != list:         return none     return list(itertools.product(shirt, tie, suit))

demo:

>>> dress_me([1,2,3],[4,5,6],[7,8,9]) [(1, 4, 7), (1, 4, 8), (1, 4, 9), (1, 5, 7), (1, 5, 8), (1, 5, 9), (1, 6, 7), (1, 6, 8), (1, 6, 9), (2, 4, 7), (2, 4, 8), (2, 4, 9), (2, 5, 7), (2, 5, 8), (2, 5, 9), (2, 6, 7), (2, 6, 8), (2, 6, 9), (3, 4, 7), (3, 4, 8), (3, 4, 9), (3, 5, 7), (3, 5, 8), (3, 5, 9), (3, 6, 7), (3, 6, 8), (3, 6, 9)]

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