javascript - New forms - embedding a collection of forms - Symfony2 -

i'm doing same explained here: http://symfony.com/doc/current/cookbook/form/form_collections.html

but in case want add new "tags" not manually clicking on link, automatically. give template array items , each of items want add new form - number of items should equal number of forms.

if it's possible, i'd prefer solution this:

{% in items %}      {{ i.name }} {{ form_widget(form.tags[loop.index0].name) }}  {% endfor %} 

but how automatically create objects in controller, too? tells me there no obeject index=1, , yes - there isn't, isn't there way create them automatically , not need create example 10 empty objects of same kind in controller? :(

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another thing thinking this:

{% in items %}   <ul class="orders" data-prototype="{{ form_widget(form.orders.vars.prototype)|e }}">  {{ i.name }} , here should field form, example tag.name   </ul>  {% endfor %} 

i suggest js given in cookbook should changed this, i'm not in js , tries didn't job.

i tried putting in loop:

<script>    addtagform(collectionholder); </script> 

and in .js file:

var collectionholder = $('ul.orders');  jquery(document).ready(function() {     collectionholder.data('index', collectionholder.find(':input').length);     function addtagform(collectionholder) {      var prototype = collectionholder.data('prototype');      var index = collectionholder.data('index');      var newform = prototype.replace(/__name__/g, index);     collectionholder.data('index', index + 1);      var $newformli = $('<li></li>').append(newform); }  }); 

assuming main class has addtag($tag) method, can add different 'new' tags it.

in class task

public function addtag($tag){     $this->tags[]=$tag;      return $this; } 

in controller (assuming 10 tags here)

$task=new task(); for($i=0;i<10;i++){    $task->addtag(new tag()); } $form->setdata($task); 

in view

{% tag in form.tags %}  <ul class="orders">     <li>{{ form_widget(tag.name) }}</li>  </ul> {% endfor %} 

if don't need manually click, can remove javascript part.